Calculer J 3 = ∫ 3 4 dx x 2 − 3 x + 2 J_3 = int from 3 to 4 { dx over sqrt {x^2 - 3x +2}}
Ecrire x 2 − 3 x + 2 x^2 - 3x +2 sous forme canonique et poser : t = 2 ( x − 3 2 ) t = 2 left ( x - 3 over 2 right ) .
Solution : J 3 = ln ( 5 + 2 6 3 + 2 2 ) J_3 = ln left ( {5 + 2 sqrt 6} over {3 + 2 sqrt 2}right )